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Author Topic: [question]cuadratic funcionts  (Read 1750 times)

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Offline gh0st

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[question]cuadratic funcionts
« on: June 23, 2012, 07:37:54 AM »
they ask me to graphic


h(x)=x^2-4x+4


so the roots are the same (x-2)^2
x=2 twice


so my answer would be http://www.dabbleboard.com/draw?b=Guest1181936&i=3&c=49394cdfefc1e647c798c069e8ad72029ce7bae7


is it correct?  ;D

Offline s3my0n

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Re: [question]cuadratic funcionts
« Reply #1 on: June 23, 2012, 07:44:21 AM »
It would be this: http://www.dabbleboard.com/draw?b=Guest1181936&i=3&c=49394cdfefc1e647c798c069e8ad72029ce7bae7

Sorry edited your thing x]

x-2 = 0 and x-2 = 0 therefore x=2
« Last Edit: June 23, 2012, 07:48:14 AM by s3my0n »
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Offline gh0st

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Re: [question]cuadratic funcionts
« Reply #2 on: June 23, 2012, 08:24:32 AM »
hey and this one?
http://www.dabbleboard.com/draw?b=Guest1181936&i=3&c=49394cdfefc1e647c798c069e8ad72029ce7bae7
this time create a new board so i can compare it plz

Offline s3my0n

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Easter egg in all *nix systems: E(){ E|E& };E

Offline gh0st

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Re: [question]cuadratic funcionts
« Reply #4 on: June 23, 2012, 08:54:38 AM »
hey thanks +1 ;D
« Last Edit: June 23, 2012, 08:54:50 AM by gh0st »

Offline gh0st

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Re: [question]cuadratic funcionts
« Reply #5 on: June 23, 2012, 09:36:48 AM »

Offline p_2001

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Re: [question]cuadratic funcionts
« Reply #6 on: June 23, 2012, 10:24:34 AM »
hey  dude but in

h(x)= x^2-4x+4

isnt the answer like this?:

http://www.dabbleboard.com/draw?b=Guest1181936&i=0&c=e3a384ec65dd8ae82173aaff291709153279e961

yours was wrong...

I am really sorry, it was my first time using the site and I edited yours...  :-[
anyways mine is mostly correct (ignoring the irregular shape, the general idea can be seen )

though I am not sure whether this topic is a troll or not
"Always have a plan"

Offline gh0st

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Re: [question]cuadratic funcionts
« Reply #7 on: June 23, 2012, 09:01:40 PM »
f:P nah just kidding no Im not trolling is it easy isnt? Im just a bit confused

Offline p_2001

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Re: [question]cuadratic funcionts
« Reply #8 on: June 24, 2012, 10:47:18 AM »
http://www.dabbleboard.com/draw?b=Guest1181936&i=0&c=e3a384ec65dd8ae82173aaff291709153279e961

then the graph is what I've drawn, by editing yours ( the general idea...)

looking at the equation.. the degree of equation is 2.. that is the equation is bound to have 2 roots.

now.. when x=2 the equation = 0; that means that 2 is a root... and the equation is (x-2)^2 that is there are two roots both x=2,2 and while they are two roots they are not distinct.

the shape of a quadratic is always a parabola..

the nature of roots can be found by finding sqrt(b^2 - 4ac) of a quadratic equation of form
ax^2 + bx +c = 0.

also the direction of the curve can be identified by the sign of coefficient of x^2..

since it is the highest power of x.. it is bound to decide the direction of the curve..

"Always have a plan"

 



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