Calculate the transmission time of a 2,000 byte file size sent over a network possessing the following characteristics:
bandwidth = 5000 HZ
report signal / noise =1000
We assume that the network uses 50 % of its Max capacity .
Ok i'll start by talking what is clear to me .
transmission time=file size/Debit
file size is equal 2000*8=16000 bits
because file size is calculated in bits and a byte has 8 bits.
Debit is the capacity used by the network
? (am not sure about this that's where i need help)
because in my solution Debit is equal to 50% max capacity=max capacity /2.
max capacity =badnwidth*log2(1+S/N) S/N is the signal / noise report
=5000 log2 1001
=49836 bit/s
debit =49836/2=24918 bit/s
transmission time= file size/Debit
=16000/24918
=0.642s
so as you've noticed the only thing i want to know is if it's true that debit is equal to the capacity used by the network
